Respuesta :
Answer:
C. its volume would remain unchanged--it would look like it did when it first left the ground
Explanation:
There is some info missing. I think this is the original question.
If a balloon was placed in a container where the pressure and temperature BOTH decreased proportionally to one another, what would the balloon look like at that point compared to initially?
HINT: proportionally means, for example, if one doubled in value, so did the other, or if one halved, so did the other, etc.
A. Â Its volume would increase due to the temperature change.
B. Â Its volume would decrease due to both the temperature and pressure changes.
C. Â its volume would remain unchanged--it would look like it did when it first left the ground
D. Â Its volume would decrease due to both the pressure change.
E. Â Its volume would increase due to both the temperature and pressure changes.
The gas initially occupies a volume Vâ at a temperature Tâ and pressure Pâ. Let's suppose that the pressure and temperature are halved (they decrease proportionally to one another). Then,
Pâ = 0.5 Pâ
Tâ = 0.5 Tâ
We can find the volume Vâ using the combined gas law.
[tex]\frac{P_{1}.V_{1}}{T_{1}} =\frac{P_{2}.V_{2}}{T_{2}} \\\frac{P_{1}.V_{1}}{T_{1}} =\frac{0.5P_{1}.V_{2}}{0.5T_{1}}\\V_{2}=V_{1}[/tex]