Answer
given,
distance = 140 m
time, t = 3.6 s
moving speed = 53 m/s
a) distance = (average velocity) x time
[tex]D = \dfrac{v_0 + v_1}{2}\times t[/tex]
[tex]140 = \dfrac{v_0 + 53}{2}\times 3.6[/tex]
v₀ + 53 = 77.78
v₀ = 24.78 m/s or 25 m/s
b) [tex]a = \dfrac{v-u}{t}[/tex]
[tex]a = \dfrac{53-25}{3.6}[/tex]
a = 7.8 m/s²
using equation of motion
v₀² = v₁² + 2 a s
53² = 0²+ 2 x 7.8 x s
s = 180 m
