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One of the deepest freedives (i.e. without any breathing apparatus) to date was achieved by Goran Colak of Serbia when he dove to a depth of 288 m in 2014. If the density of sea water is 1030 kg/m3 and the atmospheric pressure at sea level (1 atm) is 105 Pa, what is the approximate pressure experienced by Goran at that depth

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boffeemadrid

Answer:

3010038.4 Pa

Explanation:

[tex]P_0[/tex] = Atmospheric pressure = [tex]10^5\ Pa[/tex]

[tex]\rho[/tex] = Density of sea water = 1030 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth = 288 m

The total pressure at the given depth is given by

[tex]P=P_0+\rho gh\\\Rightarrow P=10^5+1030\times 9.81\times 288\\\Rightarrow P=3010038.4\ Pa[/tex]

The pressure experienced by Goran at that depth is 3010038.4 Pa

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