The reaction of 50 mL of N2 gas with 150 mL of H2 gas to form ammonia via the equation: N2 (g) 3H2 (g) --> 2NH3 (g) will produce _____ mL of ammonia if pressure and temperature are kept constant.

Respuesta :

Answer: At constant temperature and pressure, 100mL of ammonia will be produced.

Explanation:

Gay-Lussac's law of combining volumes states that the volume of gases which take part in a chemical reaction bear a simple whole number ratio to one another and to the volume of products if gaseous, when measured at constant temperature and pressure.

Equation of reaction: N₂(g) + 3H₂(g) ----> 2NH₃(g)

From the equation of reaction given above,

1 mole of nitrogen gas reacts with 3 moles of hydrogen to produce 2 moles of ammonia. Therefore,

50 mL of nitrogen will react to produce produce 2 * 50 mL of ammonia = 100ml of ammonia

Also, 150mL of hydrogen will react to produce 2 *150mL/3 of ammonia = 100ml of ammonia