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The height h (in feet) of a certain rocket t seconds after it leaves the ground is modeled by LaTeX: h\left(t\right)\:=\:-16t^2+64t+12.h ( t ) = − 16 t 2 + 64 t + 12.How long does it take the rocket to reach the maximum height?

Respuesta :

Answer:

76 feet

Step-by-step explanation:

h = -16t^2 + 64t + 12

The maximum height will be reached after -b/2a secs

a = -16 , b = 64, c= 12

-b/2a = -64/2(-16)

= -64/-32

= 2 secs

The maximum height = -16(2)^2 + 64(2) + 12

= -16(4) + 128 + 12

= -64 + 128 + 12

= 76 ft

3009827

Answer:

Answer:

76 feet

Step-by-step explanation:

h = -16t^2 + 64t + 12

The maximum height will be reached after -b/2a secs

a = -16 , b = 64, c= 12

-b/2a = -64/2(-16)

= -64/-32

= 2 secs

The maximum height = -16(2)^2 + 64(2) + 12

= -16(4) + 128 + 12

= -64 + 128 + 12

= 76 ft

Step-by-step explanation: