To solve this problem it is necessary to apply the conservation equations of the momentum, for which it allows us to find the mass of object two, which was the product of an inelastic shock. Mathematically the momentum can be described as
[tex]m_1v_1+m_2v_2 = (m_1+m_2)V_f[/tex]
Where,
[tex]m_{1,2}[/tex] = Mass of each object
[tex]v_{1,}2[/tex] = Velocity of each object
[tex]V_f[/tex]= Final Velocity
Our values are given as,
[tex]m_1 = 1 kg[/tex]
[tex]v_1 = 100 m/s[/tex]
[tex]v_2 = 0 \rightarrow[/tex] The block remains at rest
[tex]V_f = 2 m/s[/tex]
Substituting,
[tex]m_1v_1+m_2v_2 = (m_1+m_2)V_f[/tex]
[tex]1*100 + 0 = (1 + m_2)*2[/tex]
[tex]100 = 2 + 2m_2[/tex]
[tex]98 = 2m_2[/tex]
[tex]m_2 = 49 kg[/tex]
Therefore the mass of the block is 49Kg.
