Calculate the force of gravity a newborn baby of mass 3.0 kg and the obstetrician of mass 100.0 kg exert on each other when the distance between them is 0.5 m. Which exerts more gravitational force on the baby: Mars or the obstetrician?

Respuesta :

Answer:

The force of gravity a newborn and the obstetrician is 8 x [tex]10^{-8}[/tex] N.

The obstrcian exerts 1.87 times more gravitational force on the baby than the mars.

Explanation:

given information:

baby's mass, [tex]m_{1}[/tex] = 3 kg

obstericianás mass, [tex]m_{2}[/tex] = 100 kg

distance, d = 0.5 m

the formula of gravitational force is

[tex]F = \frac{Gm_{1}m_{2}  }{d^{2} }[/tex]

where

F = gravitational force (N)

G = gravitational constant (6.67 x [tex]10^{-11}[/tex])

m = mass (kg)

d = distance (m)

so, gravitational force of a newborn and the obstetrician

[tex]F = \frac{Gm_{1}m_{2}  }{d^{2} }[/tex]

         = [tex]\frac{6.67 *10^{-11} *3*100}{0.5^{2} }[/tex]

         = 8 x [tex]10^{-8}[/tex] N

thus, force of gravity a newborn and the obstetrician is 8 x [tex]10^{-8}[/tex] N

mass of mars, [tex]m_{m}[/tex] = 6.39 x [tex]10^{23}[/tex] kg

distance of mars and the earth, d = 54.6 x [tex]10^{9}[/tex] m

therefore, gravitational force of a newborn and the mars

[tex]F = \frac{Gm_{1}m_{m}  }{d^{2} }[/tex]

         = [tex]\frac{6.67 *10^{-11} *3*6.39 *10^{23}}{54.6 *10^{9}^{2} }[/tex]

         = 4.29 x [tex]10^{-8}[/tex] N

F(obstrician)/F(mars) = 8 x [tex]10^{-8}[/tex] N/4.29 x [tex]10^{-8}[/tex] N

                                     = 1.87

hence, the obstrcian exerts 1.87 times more gravitational force on the baby than the mars.