Answer:
[tex]170^{\circ} C[/tex]
Explanation:
Using the constants of copper as provided in the attached figure
We know that the change in length
[tex]\triangle L= L\triangle T \alpha[/tex]
Where [tex]\triangle l[/tex] is the change in length, L is the original length, [tex]\triangle T[/tex] is the change in temperature and [tex]\alpha[/tex] is a constant already given (attached)
Making [tex]\triangle T[/tex] the subject then
[tex]\triangle T=\frac {\triangle L}{L \alpha}[/tex]
By substitution
[tex]\triangle T=\frac {0.00130 m}{0.450 m \times 17\times 10^{-6}}=169.9346405
^{\circ} C\approx 170^{\circ} C[/tex]
