Answer:
126.99115 g
Explanation:
50 g at 90 cm
Stick balances at 61.3 cm
x = Distance of the third 0.6 kg mass
Meter stick hanging at 50 cm
Torque about the support point is given by (torque is conserved)
[tex]mgl_1=Mgl_2\\\Rightarrow M=\dfrac{ml_1}{l_2}\\\Rightarrow M=\dfrac{50\times (61.3-90)}{50-61.3}\\\Rightarrow M=126.99115\ g[/tex]
The mass of the meter stick is 126.99115 g
Answer:
127 g
Explanation:
Let m be the mass of the metre stick.
50 g mass is placed on 90 cm mark is balance at 61.3 cm mark. Take moments about the 61.3 cm mark.
Anticlockwise torque = clock wise torque
m x (61.3 - 50) = 50 x (90 - 61.3)
m x 11.3 = 50 x 28.7
m = 127 g
Thus, the mass of the mere stick is 127 g.
