Answer:
Choice C
[tex]-4\leq t\leq-3[/tex]
Step-by-step explanation:
[tex]h(t)=(t+3)^2+5[/tex]
Rate of change [tex]=h'(t)[/tex]
[tex]h'(t)=\frac{d}{dt}h(t)\\ h'(t)=2(t+3)[/tex]
For negative rate of change [tex]h'(t)\leq0[/tex]
[tex]2(t+3)\leq0\\(t+3)\leq0\\t\leq-3[/tex]
Choice C satisfies this condition.
