Respuesta :
Answer:
They all have same amount of momentum which is equal to 10 times of net force exerted on each car.
Explanation:
Given that
[tex]M_{x} > M_{y} > M_{z}[/tex]
From Newton's 2nd law of motion:
[tex]F = Ma[/tex] ---- (1)
[tex]a = \frac{F}{M}[/tex] --- (2)
Velocity is related to acceleration by:
[tex]v= at[/tex]
substituting (2) in above
[tex]v=\frac{Ft}{M}[/tex] --- (3)
Momentum is given as:
[tex]p= Mv[/tex]
[tex]p_{x} = M_{x}v \\p_{y} =M_{y} v \\ p_{z} = M_{z}v[/tex]
Using (3) in above
[tex]p_{x} = M_{x}\frac{Ft}{M_{x}}, p_{y} =M_{y} \frac{Ft}{M_{y}}, p_{z} = M_{z}\frac{Ft}{M_{z}}[/tex]
[tex]p_{x} = p_{y] = p_{z} = Ft[/tex]
We have to find momentum after 10 sec which is equal to 10 times of net force F exerted on each car.
Answer:
A-They all have the same amount of momentum
Explanation:
Mx > My > Mz
But
The net force exerted on each car is identical
That is
Fx = Fy = Fy
According the newton second law of motion
Force is directly proportional to the rate of change of momentum
F=m(v-u) / t
Ft= m(v-u)
But u=0 i.e fron rest
Ft=mv
Ft=mv(momentum)
But they all moved for 10secs
F x 10 =momentum
Momentum= 10Fx = 10Fy = 10Fz = 10F
Since Fx=Fy=Fz=F
So therefore the momentum are of the car x,y, z are similar despite having different mass but identical net force.
So we can conclude that They all have the same amount of momentum
