The force acting in the connecting rod of a engine cylinder is F = 9000 N and the crank radius R = 75 mm. If the crank makes 4200 revolutions in 1.2 minutes, then find the brake work (Wb) in kilowatts.

Respuesta :

Brake power is defined as the power developed by an engine at the output shaft.

Mathematically can be expressed as,

[tex]W_b = \frac{2\pi NT}{60*1000}[/tex]

Where,

T = Torque

N = Number of Revolution

Torque is defined as the force by the distance applied, that is

[tex]T = F*d[/tex]

[tex]T = 9000*0.075[/tex]

[tex]T= 675N\cdot m[/tex]

The number of revolution would be

[tex]N = \frac{4200}{1.2}[/tex]

[tex]N = 3500rev/min[/tex]

Finally the Brake power would be:

[tex]W_b = \frac{2\pi NT}{60*1000}[/tex]

[tex]W_b = \frac{2\pi (675N\cdot m)(3500rev/min)}{60*1000}[/tex]

[tex]W_b = 247.4W[/tex]