Answer:
[tex]^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e[/tex]
Explanation:
Beta decay conserves the lepton number. In [tex]\beta^-[/tex] decay, the atomic number of the element increases which is accompanied by the release of an electron antineutrino, [tex]e^-+\bar{v}_e[/tex].
For example:-
[tex]^A_ZX\rightarrow ^A_{Z+1}X+e^-+\bar{v}_e[/tex]
The [tex]\beta^-[/tex] decay of silicon-32 is shown below as:-
[tex]^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e[/tex]