Answer:
L= 675.2 mH
Explanation:
Given that
f= 400 Hz
Maximum voltage ,V(max)= 6 V
I(rms) = 2.5 mA
[tex]I(max)=I(rms)\sqrt{2}[/tex]
[tex]I(max)=\dfrac{V(max)}{X_L}\\I(max)=\dfrac{V(max)}{L\times 2\times \pi \times f}[/tex]
[tex]L=\dfrac{V(max)}{I(max)\times 2\times \pi \times f}[/tex]
Now by putting the values
[tex]L=\dfrac{6}{2.5\times 10^{-3}\times \sqrt2 \times 2\times \pi \times 400}[/tex]
L=0.6752
L= 675.2 m H
Inductance ,L= 675.2 mH
