Respuesta :
Answer:
There is 1.29 grams of O2 produced.
Explanation:
Step 1: Data given
Mass of ammonium perchlorate 3.8 grams
Molar mass of ammonium perchlorate = 117.49 g/mol
Step 2: The balanced equation
4NH4ClO4 → 5O2 + 6H2O + 2N2 + 4HCl
Step 3: Calculate moles of NH4ClO4
Moles NH4ClO4 = mass NH4ClO4 / molar mass NH4ClO4
Moles NH4ClO4 = 3.80 grams / 117.49 g/mol
Moles NH4ClO4 = 0.0323 moles
Step 4: Calculate moles of O2
For 4 moles of ammonium perchlorate consumed, we produce 5 moles O2, 6 moles H2O, 2 moles N2 and 4 moles HCl
For 0.0323 moles NH4ClO4 we'll have 5/4 * 0.0323 = 0.040375 moles of O2
Step 5: Calculate mass of O2
Mass O2 = moles O2 * molar mass O2
Mass O2 = 0.040375 moles * 32 g/mol
Mass O2 = 1.29 grams
There is 1.29 grams of O2 produced.
