Answer:
[tex]y =\fracc{4}{3}x+5[/tex]
m=4/3 and b=5
Step-by-step explanation:
We want to find the equation of the line passing through (3,9) and (6,13).
We determine the slope using:
[tex]m = \frac{y_2-y_1}{x_2-x_1} [/tex]
Let:
[tex](x_1=3,y_1=9), (x_2=6,y_2=13)[/tex]
We substitute the points to get:
[tex]m = \frac{13 - 9}{6 - 3} = \frac{4}{3} [/tex]
We now use the formula:
[tex]y-y_1=m(x-x_1)[/tex]
We substitute to get:
[tex]y - 9 = \frac{4}{3} (x - 3)[/tex]
Multiply through by 3 to get;
[tex]3y - 27 = 4(x - 3)[/tex]
We expand further to get:
[tex]3y - 27 = 4x - 12[/tex]
This implies that:
[tex]4x - 3y = - 15[/tex]
We solve for y to get:
[tex]y =\fracc{4}{3}x+5[/tex]
Therefore m=4/3 and b=5
