A line in the xy-plane passes through the origin and has a slope of 1/7 Which of the following points lies on the line?

A) (0, 7)
B) (1, 7)
C) (7, 7)
D) (14, 2)
E) (7, 14)

Respuesta :

Answer: Choice D.    (14, 2)

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m = 1/7 is the slope

(x,y) = (0,0) is the origin the line goes through

y = mx+b

0 = (1/7)*0 + b

0 = 0+b

b = 0 is the y intercept

y = mx+b

y = (1/7)x+0

y = (1/7)x is the equation of the line

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To plot the equation of this line, mark the point (0,0) first.

Then move up 1 unit and to the right 7 units to arrive at (7,1) as the second point.

Draw a straight line through (0,0) and (7,1) as shown in the diagram below.

Point P is (0,0) and point Q is (7,1)

Points A through E in the same diagram represent the answer choices A through E.

Of the answer choices, only point D is on this line, so point D is the answer.

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A non-visual way to find the answer is to plug each (x,y) coordinate from each answer choice into the equation we found above.

So for choice A we plug in x = 0 and y = 7

y = (1/7)*x

7 = (1/7)*0

7 = 0

we end up with a false equation, so choice A is ruled out. Similar stories happen with B, C, and E as well.

With choice D however, we plug in x = 14 and y = 2, and we get...

y = (1/7)*x

2 = (1/7)*14

2 = 14/7

2 = 2

Since we get a true equation, this confirms that (14,2) is on the graph of y = (1/7)x.

Ver imagen jimthompson5910
  • All lines passing thru the origin should have a slope of [tex]\bold{y=mx}[/tex].
  • In this case, since the slope is [tex]\bold{ \frac{1}{7}}[/tex],  the line will be  [tex]\bold{ y= \frac{1}{7}x\ \ or\ \ 7y-x=0}[/tex]
  • Thus, it could observe which is the only point [tex]\bold{(14,2)}[/tex] that satisfies this equation of the line out of all the points. As a result, only

Defining the wrong choice:

  • For choice "A" when [tex]\bold{x=0, y=7 \ and\ m =\frac{1}{7}}[/tex], and put the value in [tex]\bold{y=mx}[/tex] it will give [tex]\bold{7=0}[/tex], which is wrong.
  • For choice "B" when [tex]\bold{x=1, y=7 \ and\ m =\frac{1}{7}}[/tex], and put the value in [tex]\bold{y=mx}[/tex] it will give [tex]\bold{7=\frac{1}{7}}[/tex], which is wrong.
  • For choice "C" when [tex]\bold{x=7, y=7 \ and\ m =\frac{1}{7}}[/tex], and put the value in [tex]\bold{y=mx}[/tex] it will give [tex]\bold{7=1}[/tex], which is wrong.
  • For choice "E" when [tex]\bold{x=7, y=14 \ and\ m =\frac{1}{7}}[/tex], and put the value in [tex]\bold{y=mx}[/tex] it will give [tex]\bold{14=2}[/tex], which is wrong.

Therefore, "Choice D" is the correct choice.

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Ver imagen codiepienagoya