Respuesta :
Explanation:
Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.
This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.
Increase the volume:
If the volume of the container is increased, the pressure will decrease according to Boyle's Law. Now, according to the Le-Chatlier's principle, the equilibrium will shift in the direction where increase in pressure is taking place. So, the equilibrium will shift in a direction where more number gaseous moles are present.
A) [tex]2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)[/tex]
Number of gaseous moles on reactant side = 2
Number of gaseous moles on product side = 2
Equilibrium will not shift any direction as on both sides number of gaseous moles are same.
B) [tex]2NO(g)+O_2(g)\rightleftharpoons 2NO_2(g)[/tex]
Number of gaseous moles on reactant side = 3
Number of gaseous moles on product side = 2
Equilibrium will shift any left direction.
C) [tex]2N_2O_5(g)\rightleftharpoons 4NO_2(g)+O_2[/tex]
Number of gaseous moles on reactant side = 2
Number of gaseous moles on product side = 5
Equilibrium will shift any right direction.
D) [tex]2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)[/tex]
Number of gaseous moles on reactant side = 3
Number of gaseous moles on product side = 2
Equilibrium will shift any left direction.
E) [tex]PCl_5\rightleftharpoons PCl_3(g)+Cl_2(g)[/tex]
Number of gaseous moles on reactant side = 1
Number of gaseous moles on product side = 2
Equilibrium will shift any right direction.