There is one mistake in the question is values of q(t) is not correctly written.The Correct question is here
A mysterious device found in a forgotten laboratory accumulates charge at a rate specified by the expression q(t) = 9−10t C from the moment it is switched on. (a) Calculate the total charge contained in the device at t = 0. (b) Calculate the total charge contained at t = 1 s. (c) Determine the current flowing into the device at t = 1 s, 3 s, and 10 s.
Answer:
(a) q(t)=9 C at t=0 s
(b) q(t)=-1 C at t=1 s
(c) I= -10 A at t=1 s , I= -10 A at t=3 s , I= -10 A at t=10 s
Explanation:
Given Data
q(t)=9-10t C
(a) t=0 s
(b) t=1 s
(c) t=1 s , t=3 s , t=10 s,
To Find
(a) q(t) at t=0 s
(b) q(t) at t=1 s
(c) I(current)
Solution
For part (a) of question
q(t)=9-10×t
at t=0 s
q(t)=9-10×(0)
q(t)= 9 C
For part (b) of question
q(t)=9-10×t
at t=1 s
q(t)=9-10×(1)
q(t)= -1 C
For part (c) of question
q(t)=9-10×t
as
[tex]I=\frac{dq}{dt}\\ I=\frac{d}{dt}(9-10t)\\ I=-10A[/tex]
At t=1 s
I=-10 A
At t=3 s
I=-10 A
At=10 s
I=-10 A
