Answer:
[tex]\overrightarrow{F} = -\left ( 15x^{4}y-3 \right )\widehat{i}-3x^{5}\widehat{j}[/tex]
Explanation:
[tex]U = 3x^{5}y-3x[/tex]
Force is defined as the
[tex]\overrightarrow{F} = -\frac{dU}{dx}\widehat{i}-\frac{dU}{dy}\widehat{j}[/tex]
[tex]\frac{dU}{dx}=15x^{4}y-3[/tex]
[tex]\frac{dU}{dy}=3x^{5}[/tex]
So, force is given by
[tex]\overrightarrow{F} = -\left ( 15x^{4}y-3 \right )\widehat{i}-3x^{5}\widehat{j}[/tex]