Answer:
24 m
Explanation:
initial velocity is u = 3.5 m/sec
final velocity is v = 0 m/sec
distance traveled is S = 1.5 m
From kinematic equation [tex]v^{2}-u^{2} = 2as[/tex]
Making acceleration the subject,
[tex]a=\frac {v^{2}-u^{2}}{2s}[/tex]
Acceleration [tex]a = \frac {0^2-3.5^2}{(2*1.5)}= -4.083333333m/s^{2}[/tex]
When the initial velocity is quadrupled= u = 3.5*4 = 14 m/s
V = 0 m/s
[tex]a = -4.083333333m/s^{2}[/tex]
then [tex]S = \frac {v^{2}-u^{2}}{2} = \frac {0^{2}-14^{2}}{2\times -4.083333333} = 24 m[/tex]
