Answer:
The change in kinetic energy is 5,909,400J and the terminal speed of the car is 160,800mph
Explanation:
Change in kinetic energy = mg(h2 - h1)
Mass (m) = 1500kg, g = 9.8m/s^2, final distance (h2) = 402m, initial distance (h1) = 0m
Change in kinetic energy = 1500×9.8×(402 - 0) = 1500×9.8×402 = 5,909,400J
From equations of motion
h = ut + 1/2gt^2 [u is initial speed and is equal to zero because the car drag racing began from a standing start (rest)]
h = 1/2gt^2
402 = 1/2 × 9.8t^2
402 = 4.9t^2
t^2 = 402/4.9 = 82.04
t = √82.04 = 9.06s × 1h/3600s = 0.0025h
Terminal speed = distance/time = 402m/0.0025h = 160,800mph
