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a stationary bomb of mass 5kg exploded into one part A of mass 2kg flying off with a velocity of 60 m/s and another part B of mass 3kg flying off with a velocity v in the opposite direction. find v and the total Kinetic energy​

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MathPhys

Explanation:

Momentum before = momentum after

(5 kg) (0 m/s) = (2 kg) (60 m/s) + (3 kg) v

v = -40 m/s

Total kinetic energy is:

KE = ½ (2 kg) (60 m/s)² + ½ (3 kg) (-40 m/s)²

KE = 6000 J

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