Answer:
V = 2.94cm³
The initial volume at 20°C is 2.94cm³
Explanation:
As the temperature of the iron sphere increases the volume of the sphere also increase.
Using the equation for volumetric expansion:
∆V = VαΔT
where ;
V is the initial volume
α is the volumetric expansion coefficient
∆V is the change in Volume
∆T is the change in temperature
After Expansion the final volume can be written as:
Vf = V + ∆V
Vf = V + VαΔT
Vf = V(1 + αΔT)
making V the subject of formula;
V = Vf/(1+αΔT) .....1
Given:
Vf = 3.00cm³
ΔT= 600-20 = 580
And from the test book.
α = 35.5 × 10⁻⁶K⁻¹
Substituting the values into eqn 1
V = 3.00/(1+580× 35.5×10^-6)
V = 3.00/(1+0.021) = 3.00/1.021
V = 2.94cm³
The initial volume at 20°C is 2.94cm³
Answer: 1cm3
Explanation:
V1 =?
V2 = 3cm3
T1 = 20°C = 20 + 273 = 293K
T2 = 600°C = 600 + 273 = 873K
V1 /T1 = V2 /T2
V1 / 293 = 3 / 873
V1 = 293 x ( 3 / 873)
V1 = 1 cm3
