The solution is (-7,5)
Step-by-step explanation:
In Linear Combination method, the co-efficient of any one variable in the equation is made opposite to each other so that it might cancel out later by adding the equations
Given equations are:
[tex]2x + 3y = 1\ \ \ \ Eqn1\\y = -2x-9\\2x-y = -9\ \ \ \ \ Eqn2[/tex]
We can see that the coefficient of x is already same, we have to multiply the second equation by -1 to make the co-efficient opposite
So,
Multiplying Equation 2 by -1
[tex]-2x-y=9\ \ \ \ Eqn3[/tex]
Adding Equation 1 and Equation 3
[tex]2x+3y-2x-y = 1+9\\2y = 10[/tex]
Dividing both sides by 2
[tex]\frac{2y}{2} = \frac{10}{2}\\y = 5[/tex]
Putting y = 5 in equation 1
[tex]2x+3(5) = 1\\2x+15 = 1\\2x = 1-15\\2x = -14[/tex]
Dividing both sides by 2
[tex]\frac{2x}{2} = \frac{-14}{2}\\x = -7[/tex]
Hence,
The solution is (-7,5)
Keywords: Linear equations, variables
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