The solution is (-4,4)
Step-by-step explanation:
Given equations are:
[tex]4x-9y = 20\ \ \ \ Eqn1\\2x-6x = 16\ \ \ \ Eqn2[/tex]
In linear combination method, we have to make coefficients of any one variable opposites by multiplying with an integer
So multiplying 2nd equation by -2
[tex]-2(2x-6y=16)\\-4x+6y=-32\ \ \ \ Eqn3[/tex]
Adding Equation 1 and Equation 3:
[tex]4x-9y-4x+12y = 20-32\\3y = -12[/tex]
Dividing both sides by 3
[tex]\frac{3y}{3} = \frac{-12}{3}\\y = -4[/tex]
Putting y=-4 in equation 1
[tex]4x-9(-4) = 20\\4x +36= 20\\4x = 20-36\\4x = -16[/tex]
Dividing both sides by 4
[tex]\frac{4x}{4} = \frac{-16}{4}\\x = -4[/tex]
Hence,
The solution is (-4,4)
Keywords: Linear combination, linear equations
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