Answer:
Hey, Dalilah. I hope I'm not too late, but the answer is (3,5).
Step-by-step explanation:
You have to use the equation that includes the x value of 3.
4x+1 only includes x values that are less than 3.
2x-1 includes x values that are greater than or equal to 3.
I plugged 3 into both of these equations (4x+1; x < 3 & 2x-1; x ≥ 3) in order to see which equation would've been true.
4(3)+1 = 13; 13 < 3 [False] 13 isn't less than 3 -- and 2(3)-1 = 5; 5 ≥ 3 [True] 5 is greater than or equal to 3.
Since the equation 2(3)-1; 5≥3 is true, you should use this equation. I used Demos in order to graph Y=2(3)-1. At the bottom of that I put x=3, and it showed me (3,5).
I'll post the pictures for proof and better clarification if this is confusing, love.
