Answer:
2387350 Nm
0.929 degrees
Explanation:
w = 2*pi*f = 2*pi*600/60 = 62.831 rad/s
Given data:
P = 300*10^3 W ; G = 75 GPa ; d = 0.1m ; r = 0.05m
[tex]J = \frac{pi * c^4}{2} = \frac{pi * r^4}{2} = \frac{pi * 0.05^4}{2} = 9.8175*10^(-6) m^4\\\\T = \frac{P}{w} = \frac{300,000}{62.831} = 4774710 Nm\\\\TC = TB = 0.5*T = 2387350 Nm\\[/tex]
Tmax is the torque at any point of part AB and is equal to T generated at point A, and from B to D the power and torque will be removed by gears.
[tex]t_{max} = \frac{T*r}{J} = \frac{4774710*0.05}{9.8175*10^(-6)}=24.3MPa\\\\Q_{D/A} = sum (\frac{T*L}{J*G}) = \frac{TAB*LAB}{J*G} + \frac{TBC*LBC}{J*G} \\\\= \frac{4774710*1.5}{(9.8175*10^(-6)) * 79 * 10^9} + \frac{2387350*2}{(9.8175*10^(-6)) * 79 * 10^9}\\\\= 0.01621 rad\\\\Q_{D/A} = 0.01621 * \frac{180}{pi} = 0.929 degrees[/tex]
