Respuesta :
Answer:
The displacement, velocity and time is 20.4 m, -4.52 m/s and 3.624 sec.
Explanation:
Given that,
Initial velocity =15.0 m/s
Height = 10 m
We need to calculate the displacement at 2 sec
Using equation of motion
[tex]s=ut-\dfrac{1}{2}gt^2+s_{0}[/tex]
Put the value into the formula
[tex]s=15t-\dfrac{1}{2}\times9.8\times t^2+10[/tex]
At 2 sec,
[tex]s=15\times2-\dfrac{1}{2}\times9.8\times4+10[/tex]
[tex]s=20.4\ m[/tex]
We need to calculate the time
Using equation of motion again
[tex]s=15t-\dfrac{1}{2}\times9.8\times t^2+10[/tex]
At ground s = 0,
[tex]15t-\dfrac{1}{2}\times9.8\times t^2+10=0[/tex]
[tex]4.9t^2-15t-10=0[/tex]
[tex]t = 3.624\ sec[/tex]
Neglect the negative term because the time is not negative
We need to calculate the velocity
Using formula of velocity
[tex]v=u-gt[/tex]
[tex]v=15-9.8\times3.624[/tex]
[tex]v=-4.52\ m/s[/tex]
Hence, The displacement, velocity and time is 20.4 m, -4.52 m/s and 3.624 sec.
