Answer:
Therefore the missing term is
[tex]\dfrac{5}{4}[/tex]
And the Sequence is
[tex]1,\dfrac{3}{2},\dfrac{5}{4},\dfrac{7}{8},\dfrac{9}{16}[/tex]
Step-by-step explanation:
The Missing Pattern in b>
The given Sequence is
[tex]1,\dfrac{3}{2},\ ...\ ,\dfrac{7}{8},\dfrac{9}{16}[/tex]
To Find:
Missing one
Solution:
In this Pattern two is added to the numerator and two is multiplied by the denominator for the next term.
First term is
[tex]\dfrac{1}{1}[/tex]
Now for the second term, add two do the numerator and multiply two the denominator we get,
[tex]\dfrac{1+2}{1\times 2}=\dfrac{3}{2}[/tex]
Similarly for the third term do the same process we get
[tex]\dfrac{3+2}{2\times 2}=\dfrac{5}{4}[/tex]
Further for the fourth term we will get
[tex]\dfrac{5+2}{4\times 2}=\dfrac{7}{8}[/tex]
and so on.
Therefore the missing term is
[tex]\dfrac{5}{4}[/tex]
And the Sequence is
[tex]1,\dfrac{3}{2},\dfrac{5}{4},\dfrac{7}{8},\dfrac{9}{16}[/tex]
