Respuesta :
The butterfly takes a vertical perpendicular path equivalent to 9m and travels a horizontal distance of 17m. The net path between the two is equivalent to that of the hypotenuse, so we will apply the Pythagorean theorem.
[tex]x=\sqrt{(9)^2+(0.17)^2}[/tex]
[tex]x = 9.0061 \approx 9.0 m[/tex]
Therefore the magnitude of the butterfly's displacement is 9m

Answer:
R=12 m
Explanation:
I have drawn a vector form which I attached here.Please first go through that
Given Data
y (Tree Taller) = 9.0 m
x(Distance from center to edge is)= 8.5 m
To find
R(magnitude of the butterfly's displacement
)
Solution
[tex]R=\sqrt{x^{2} +y^{2} }\\R=\sqrt{9^{2}+8.5^{2} }\\ R=12.379m[/tex]
Convert to two significant figures
R=12 m
