he cost of [tex]2\frac{1}{2}[/tex] pounds of cheese s $10
Solution:
Method 1:
Cost of one pound of cheese = $4
Cost of 2 pounds of cheese = [tex]\$4\times2=\$8[/tex]
Cost of [tex]\frac{1}{2}[/tex] pound of cheese = [tex]\$4\times0.5=\$2[/tex]
Therefore, the cost of [tex]2\frac{1}{2}[/tex] pounds of cheese = 8+2=$10
Method 2:
If one pound of cheese costs $4 then, the cost of [tex]2\frac{1}{2}[/tex] (i.e 5/2) pounds of cheese = [tex]\$4\times\frac{5}{2}=\$10[/tex]
Therefore, [tex]2\frac{1}{2}[/tex] pounds of cheese costs $10