Calculate the volume in milliliters of a 0.92M nickel(II) chloride solution that contains 175. mmol of nickel(II) chloride NiCI2). Round your answer to 2 significant digits.

Respuesta :

Answer:

The volume of the solution is 190 milliliters.

Explanation:

[tex]Molarity(M)=\frac{n}{V(L)}[/tex]

Where :

n = moles of compound

V = Volume of solution in L

M = Molarity of solution

Moles of nickel(II) chloride = n  = 175 milli mol = 0.175 mol

1 milli mol = 0.001 mol

Volume of nickel(II) chloride solution = V

Molarity of the nickel(II) chloride = 0.92 M

[tex]0.92 M=\frac{0.175 mol}{V}[/tex]

[tex]V=\frac{0.175 mol}{0.92 M}=0.1902 L[/tex]

1 L = 1000 mL

V = 0.1902 L= 0.1902 × 1000 mL =  190.2 mL ≈ 190 mL

The volume of the solution is 190 milliliters.