Answer:
The correct option is third one m∠2 =106° , m∠3 =37°.
Therefore,
[tex]m\angle 2 = 106\°\\m\angle 3 = 37\°[/tex]
Step-by-step explanation:
Given:
Consider ABCD as a Rhombus such that,
∠A = ∠1 = 106°
∠C = ∠2
∠BDC = ∠3
AB=BC=CD=DA
To Find:
∠2 = ?
∠3 = ?
Solution:
ABCD is a Rhombus
∠A ≅ ∠C ............opposite angles of Rhombus are equal. ( property )
Substituting the values we get
∠1 = ∠2
But ∠1 = 106°
∴ ∠2 = 106° ....... Transitive property,
As BC = CD ...Given
ΔBCD is an Isosceles triangle
∴ ∠CBD ≅ ∠BDC = ∠3 ........base angle of Isosceles triangle are congruent.
we know that in a triangle,
Sum of measures of all angles is 180°
in Triangle BCD
[tex]\angle 3 +\angle 2 +\angle 3 =180[/tex]
Substituting the values we get
[tex]2m\angle 3 =180-106=74\\\\\angle 3=\dfrac{74}{2}=37\\\\m\angle 3 = 37\°[/tex]
Therefore,
[tex]m\angle 2 = 106\°\\m\angle 3 = 37\°[/tex]
