Respuesta :
Answer: The p-function of [tex]Zn^{2+}[/tex] and [tex]NO_3^{-}[/tex] ions are 2.51 and 2.14 respectively.
Explanation:
p-function is defined as the negative logarithm of any concentration.
We are given:
Millimolar concentration of zinc nitrate = 3.1 mM
Millimolar concentration of calcium nitrate = 4.2 mM
Converting this into molar concentration, we use the conversion factor:
1 M = 1000 mM
- Concentration of zinc nitrate = 0.0031 M = 0.0031 mol/L
1 mole of zinc nitrate produces 1 mole of zinc ions and 2 moles of nitrate ions
Concentration of zinc ions = 0.0031 M
Concentration of nitrate ions in zinc nitrate, [tex]M_1=(2\times 0.0031)=0.0062M[/tex]
- Concentration of calcium nitrate = 0.0042 M = 0.0042 mol/L
1 mole of calcium nitrate produces 1 mole of calcium ions and 2 moles of nitrate ions
Concentration of calcium ions = 0.0042 M
Concentration of nitrate ions in calcium nitrate, [tex]M_2=(2\times 0.0042)=0.0084M[/tex]
To calculate the concentration of nitrate ions in the solution, we use the equation:
[tex]M=\frac{M_1V_1+M_2V_2}{V_1+V_2}[/tex]
Putting values in above equation, we get:
[tex]M=\frac{(0.0062\times 1)+(0.0084\times 1)}{1+1}\\\\M=0.0073M[/tex]
Calculating the p-function of zinc ions and nitrate ions in the solution:
- For zinc ions:
[tex]\text{p-function of }Zn^{2+}\text{ ions}=-\log[Zn^{2+}][/tex]
[tex]\text{p-function of }Zn^{2+}\text{ ions}=-\log(0.0031)\\\\\text{p-function of }Zn^{2+}\text{ ions}=2.51[/tex]
- For nitrate ions:
[tex]\text{p-function of }NO_3^{-}\text{ ions}=-\log[NO_3^{-}][/tex]
[tex]\text{p-function of }NO_3^{-}\text{ ions}=-\log(0.0073)\\\\\text{p-function of }NO_3^{-}\text{ ions}=2.14[/tex]
Hence, the p-function of [tex]Zn^{2+}[/tex] and [tex]NO_3^{-}[/tex] ions are 2.51 and 2.14 respectively.
