Answer:
The force will be doubled.
Explanation:
Just looking at the situation,
We are supposing the distance in between these charges is the same in both the cases which is r, so for the first normal case,
[tex]F_1=q_1q_2/r^2[/tex], q1, q2 are the two charges and r is the distance between them.
Now take the other case when the the Charges are doubled,
[tex]F_2=2(q_1q_2)/r^2\\F_2=2(F_1)[/tex]
you can see clearly from the above equation that the new force which is [tex]F_2[/tex] has been doubled.
I hope it helps,
Thank you.