The time of flight is 3.54 s
Explanation:
The motion of the cell phone is a free fall motion (constant acceleration, [tex]g=9.8 m/s^2[/tex], towards the ground), since it is acted upon the force of gravity only: therefore, we can use the following suvat equation
[tex]s=ut+\frac{1}{2}at^2[/tex]
where:
s = 61.3 m is the vertical displacement of the phone
u = 0 is the initial vertical velocity
[tex]a=g=9.8 m/s^2[/tex] is the acceleration
t is the time of flight of the phone
Solving for t, we find:
[tex]t=\sqrt{\frac{2s}{g}}=\sqrt{\frac{2(61.3)}{9.8}}=3.54 s[/tex]
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