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An electronic package with a surface area of 1 m2 placed in an orbiting space station is exposed to space. The electronics in this package dissipate all 1850 W of its power to space through its exposed surface. The exposed surface has an emissivity of 1.0 and an absorptivity of 0.25. Given: σ = 5.67×10–8 W/m2·K4

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princessesther2011

Answer:

The temperature of the electronic package is 425K

Explanation:

Using the Stefan Boltzmann's equation,

Power dissipated = emissivity × stefan boltzmann constant × area of object × the fourth power of the temperature of the object in Kelvin

Power dissipated = 1850W, emissivity = 1.0, stefan boltzmann constant = 5.67×10^-8W/m^2K^4, area of electronic package = 1m^2

1850 = 1 × 5.67×10^-8 × 1 × T^4

T^4 = 1850/5.67×10^-8 = 3.26×10^10

T^4 = 3.26×10^10

T = (3.26×10^10)^1/4 = 425K

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