Answer:
Yes, the unknown substance is the liquid ethylene glycol.
Explanation:
Here the density of the unknown substance is 69.22lb/f and the density of ethylene glycol, the liquid used in antifreeze is 1.1088g/ml
We know, 1g = 0.0022lb
1ml= [tex]3.531 \times 10^{-5} ft^3[/tex]
Therefore, 1g/ml = 62.428[tex]lb/ft^3[/tex]
Since, the density of ethylene glycol = 1.1088g/ml
= 1.1088 [tex]\times[/tex] 62.428 [tex]lb/ft^3[/tex]
= 69.22 [tex]lb/ft^3[/tex]
When the density of ethylene gas is converted from g/ml unit to [tex]lb/ft^3[/tex] unit, it is found to have the same value (69.22)Therefore, the unknown substance here is liquid ethylene glycol.
