Answer:
His diagonal brace need to be 15.55 feet long in the kitchen.
Step-by-step explanation:
Given : The wall of the kitchen is in the shape of a square.
Area of the wall = 121 sq ft
Let us assume the each side of wall = a ft
Now, AREA OF THE SQUARE = Side x Side
⇒ a x a = 121 sq units
[tex]\implies a ^2 = 121\\\implies a = 11[/tex]
So, each side of the kitchen wall is 11 ft.
Now,as we know in a square : EACH ANGLE IN THE SQUIRE IS A RIGHT ANGLE.
So, by Pythagoras Theorem, Diagonal D is:
[tex]D^2 = a^2 + a^2\\\implies D^2 = 11^2 + 11^2 = 121 + 121\\\implies D^2 = 242\\\implies D = 15.55[/tex]
Hence, his diagonal brace need to be 15.55 ft long in the kitchen.
