The question is incomplete, here is the complete question:
Calculate the volume in liters of a [tex]8.75\times 10^{-5}M[/tex] silver (II) oxide solution that contains 200.g of silver (II) oxide . Round your answer to 3 significant digits.
Answer: The volume of solution is [tex]1.84\times 10^4L[/tex]
Explanation:
To calculate the volume of solution, we use the equation used to calculate the molarity of solution:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}[/tex]
We are given:
Molarity of solution = [tex]8.75\times 10^{-5}M[/tex]
Given mass of silver (II) oxide = 200. g
Molar mass of silver (II) oxide = 124 g/mol
Putting values in above equation, we get:
[tex]8.75\times 10^{-5}M=\frac{200}{124\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{200}{124\times 8.75\times 10^{-5}}=1.84\times 10^4L[/tex]
Hence, the volume of solution is [tex]1.84\times 10^4L[/tex]
