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At a certain location, Earth has a magnetic field of 0.60 â 10â4 T, pointing 75° below the horizontal in a north-south plane. A 14.6 m long straight wire carries a 11 A current
a) If the current is directed horizontally toward the east, what are the magnitude and direction of the magnetic force on the wire?
b) What are the magnitude and direction of the force if the current is directed vertically upward?

Respuesta :

Answer:

a)   [tex] = 9.30\times 10^{-3} N[/tex]

b) [tex]= 2.49\times 10^{-3} N[/tex]

Explanation:

Given data;

magnetic field [tex]= 0.60 \times 10^{-4}  T[/tex]

current I = 11 A

length of wire L = 14.6 m

Angle[tex] \theta = 75 A[/tex]

a) Magnetic force due to current

[tex]F = BIL sin \theta[/tex]

 [tex] = 0.60 \times 10^{-4} \times 11 \times 14.6 sin 75^o[/tex]

 [tex] = 9.30\times 10^{-3} N[/tex]

B) magnitude of force due upward current direction

[tex]F = BIL sin \theta[/tex]

  [tex]= 0.60 \times 10^{-4} \times 11 \times 14.6 sin (75^o + 90^o)[/tex]

[tex]= 2.49\times 10^{-3} N[/tex]

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