Respuesta :
Explanation:
The mass of carbon and hydrogen is calculated from the mass of their oxides ([tex]CO_{2}[/tex] and [tex]H_{2}O[/tex]) as follows.
Mass of C = [tex]3.00 g CO_{2} \times \frac{12.01 g C}{44.0 g CO_{2}}[/tex]
= 0.818 g C
Mass of H = [tex]1.23 g CO_{2} \times \frac{2.016 g H}{18.02 g H_{2}O}[/tex]
= 0.137 g H
So, the mass of C + mass of H is as follows.
0.818 g + 0.137 g = 0.955 g
This mass is actually less than the mass of sample. And, the missing mass must be caused by O. Hence, the mass of O will be calculated as follows.
Mass of O = 1.50 g - 0.955 g
= 0.545 g
Now, we convert masses to moles and find their moles and ratio as follows.
Element Mass/g Moles Ratio [tex]\times 2[/tex] Integers
C 0.818 0.068 1 2 2
H 0.137 0.068 1 2 2
O 0.545 0.0340 0.5 1 1
Thus, we can conclude that simplest formula for the given compound is [tex]C_{2}H_{2}O[/tex].
The simplest formula of the compound is CH2O.
We must obtain the number of moles of carbon, hydrogen and oxygen as follows;
Mass of carbon = 3.00 g × 12g/44 g = 0.82 g
Number of moles of carbon = 0.82 g/12 g/mol = 0.068 moles
Mass of hydrogen = 1.23 g × 2/18 = 0.14 g
Number of moles of hydrogen = 0.14 g/ 1 g/mol = 0.14 moles
Mass of oxygen = 1.5g - (0.82 g + 0.14 g) = 1.39 g
Number of moles of oxygen = 1.39g/16g/mol = 0.087 moles
Now, we have to divide through by the lowest ratio;
C - 0.068/0.068 H - 0.14/0.068 O = 0.087/0.068
C - 1 H - 2 O- 1
The simplest formula of the compound is CH2O.
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