Option A
The equation of line is [tex]y = \frac{-3}{4}x - 3[/tex]
Solution:
Given that line passes through the point (4, –6) and has a slope of Negative three-fourths
Given point is (x, y) = (4, -6)
[tex]slope = \frac{-3}{4}[/tex]
The equation of line passing through point (x, y) and slope "m" is given as:
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Substitute (x, y) = (4, -6) and [tex]m = \frac{-3}{4}[/tex] in eqn 1
[tex]-6 = \frac{-3}{4} \times 4 + c\\\\-6 = -3 + c\\\\c = -6 + 3\\\\c = -3[/tex]
The required equation of line is given as:
[tex]\text{ Substitute } m = \frac{-3}{4} \text{ and } c = -3 \text{ in eqn 1 }[/tex]
[tex]y = \frac{-3}{4}x - 3[/tex]
Thus the equation of line is found
Answer:
the answer is A
Step-by-step explanation:
Hope this helps!
