Respuesta :
Answer:
The answer to your question is letter C.
Explanation:
Reaction
Potassium hydroxide = KOH
Barium chloride = BaClâ‚‚
Potassium chloride = KCl
Barium hydroxide = Ba(OH)â‚‚
      KOH  +  BaCl₂   ⇒   KCl  +  Ba(OH)₂
     Reactant     Elements    Products
        1           K            1
        1           Ba           1
        2           Cl           1 Â
        1           H           2
        1           O           2
The reaction is unbalanced
    2KOH  +  BaCl₂   ⇒  2KCl  +  Ba(OH)₂
     Reactant     Elements    Products
        2           K           2
        1           Ba           1
        2           Cl           2 Â
        2            H           2
        2           O           2
Now, the reaction is balanced
Answer: C.
2KOH + BaCl2 => 2KCl + Ba(OH)2
Explanation:
There are 2 atoms of O and H in Ba(OH)2 in the product so to balance we put 2 on KOH. Then balance K by adding 2 in KCl to have equal number of atoms for K and Cl in both the reactant and product side. Barium have 1 atom on the reactant and in the product.