Respuesta :
Answer:
The molarity is 8.52M
Explanation:
molality = moles of solute/kg of solvent = 5.2mol/kg
moles of solute = 5.2mole
mass of solute = moles of solute × MW = 5.2 × 56.106 = 291.8g
mass of solvent = 1kg = 1000g
mass of solution = mass of solute + mass of solvent = 291.8g + 1000g = 1291.8g
Density of KOH = 2120g/L
Volume of solution = mass/density = 1291.8/2120 = 0.61L
Molarity = number of moles of solute/volume of solution = 5.2/0.61 = 8.52M
The molarity of the KOH solution has been 8.52 M.
The molality has been defined as moles of solute per kg of solvent. Molarity has been defined as moles of solute in the liter of solution.
Computation for Molarity of KOH
The given molality of KOH has been 5.2 mol/kg. Thus, 5.2 moles of KOH has been present in 1000 g of solvent.
The mass of KOH in 5.2 mol has been:
[tex]\rm Mass=Moles\;\times\;Molar\;mass\\ Mass=5.2\;\times\;56.106\\ Mass=291.8\;g[/tex]
The mass of KOH in the solution has been 291.8 g.
The mass of solvent has been 1000 g.
Thus, the mass of solution has been:
[tex]\rm Mass\;solution=solute\;+\;solvent\\ Mass\;solution=291.8\;+\;1000\;g\\ Mass\;solution=1291.8\;g[/tex]
The density of KOH has been 2120 g/L.
[tex]\rm 2120\;g Mass=1\;L Volume\\\\ 1291.8\;g=\dfrac{1}{2120} \;\times\;1291.8\;L\\\\ 1291.8\;g=0.61\;L[/tex]
The volume of the KOH solution has been 0.61 L.
The molarity of the solution has been given as:
[tex]\rm Molarity=\dfrac{Moles}{Volume}\\\\ Molarity=\dfrac{5.2}{0.61}\\\\ Molarity=8.52\;M[/tex]
The molarity of the KOH solution has been 8.52 M.
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