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A personnel manager is concerned about absenteeism. She decides to sample employee records to determine if absenteeism is distributed evenly throughout the six-day workweek. The null hypothesis is: Absenteeism is distributed evenly throughout the week. Use the 0.01 level of significance. The sample results are: Day of the Week No. of Employees Absent Monday 12 Tuesday 9 Wednesday 11 Thursday 10 Friday 9 Saturday 9 How many degrees of freedom are there?

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Answer:

There are 5 degrees of freedom.

Explanation:

If we want to find the degree of freedom in a chi-square check, the sample size was ' n ' then the number of degrees of freedom to be used in measurements would be n-1.

For a sample size of N=6, measure the degrees of freedom. Subtract 1 (df=6-1=5) from 6. of freedom in chi- square test .

  • Degree of freedom = (N-1).
  • Degree of freedom = (6-1)
  • Degree of freedom = (5)

therefore, the value of df is 5.

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