Answer:
98.9 kPa
Explanation:
given,
Pressure reading of barometer = 742 mm Hg
we know,
760 mm Hg = 1.013 x 10⁵ Pa
[tex]1\ mm\ Hg = \dfrac{1.013\times 10^5}{760}[/tex]
[tex]742\ mm\ Hg = \dfrac{1.013\times 10^5}{760}\times 742[/tex]
= 0.989 x 10⁵ Pa
= 98.9 x 10³ Pa
= 98.9 kPa
the reading of the barometer is equal to 98.9 kPa
The pressure reading from the barometer expressed in kilopascal is 98.9kPa.
Given that;
Pressure reading from the barometer; [tex]P = 742mmHg[/tex]
Pressure reading from the barometer in kilopascals; [tex]x = \ ?[/tex]
First we convert the units from Millimeter of Mercury (mmHg) to Pascal (Pa)
We are to use;
[tex]760 mm Hg = 1.013 * 10^5 Pa\\\\\frac{760mmHg}{760} = \frac{1.013 * 10^5 Pa}{760} \\\\1mmHg = 1.33289 * 10^2 Pa[/tex]
So,
Pressure reading is pascal
[tex]P = 742 * [1.33289*10^2Pa]\\\\P = 98900.438Pa[/tex]
Next we convert to kilopascal
We know that; [tex]1\ Pascal = 0.001\ kilopascal[/tex]
so
[tex]P = 98900.438 * 0.001 kPa\\\\P = 98.9kPa[/tex]
Therefore, the pressure reading from the barometer expressed in kilopascal is 98.9kPa.
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