Show that DEFG is a rectangle.

Answer:
opposite sides that are parallel,
opposite angles that are congruent,
opposite sides that are congruent,
consecutive angles that are supplementary, and
diagonals that bisect each other.
Step-by-step explanation:
not sure if this is the kind of answer you're looking for so i'm sorry if this didn't help
Answer:
in the steps
Step-by-step explanation:
D(-2,3) E(4,-1) F(2,-4) G(-4,0)
slope DG: (0-3)/(-4+2) = -3/-2 = 3/2
slope EF: (-4+1)/(2-4) = -3/-2 = 3/2
DG // EF
slope DE: (-1-3)/(4+2) = -4/6 = -2/3
slope GF: (-4-0)/(2+4) = -4/6 = -2/3
DE // GF
slope DG = - 1/slope DE
DG ⊥ DE
The same reason
DG ⊥ GF
DE ⊥ EF
EF ⊥ GF
∴ DEFG is a parallelogram with four 90° interior angles, it's a rectangle