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A can company makes a cylindrical can that has a radius of 6 cm and a height of 10 cm. One of the company's
clients needs a cylindrical can that has the same volume but is 15 cm tall. What must the new radius be to meet the
client's need? Round to the nearest tenth of a centimeter.
2.7 cm
4.9 cm
O 7.3 cm
24.0 cm

Respuesta :

Your answer to this question is 4.9 cm
devishri1977

Answer:

Step-by-step explanation:

V=πr²h

=3.14*6*6*10

=1130.4 cm³

New cylinder:

h = 15cm

V= 1130.4  cm³

πr²h = 1130.4

3.14*r²*15=1130.4

r²=1130.4/15*3.14

r²=24

r=√24

r=4.898 = 4.9 cm

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